Question

Rezolvati in R ecuatiile: 7x-49=0, 3x-11=0, -3supra 4 x+5 supra 6=0
Rezolvati in Q ecuatiile: -3x+27=0; 2(x-1)+3x=-x+1; 2(1-x)+3(x-2)=4(x-5)+3
Va rooooooooooog ajutatima DAU COROANA

Answer 1

7 x = 49  ⇒ x = 49 : 7 ⇒ x = 7 ∈ R

3 x - 11 = 0 ⇒ 3 x = 11 ⇒ x = 11/3 = 3,(6) 

- 3/4 x + 5/6 = 0 ⇒ - 3/4 x = - 5/6  l (: - )

⇒  5 × 4 x = 6 × 3 ⇒ 20 x = 18 ⇒ x = 18/20 = 9/10 ∈Q

2 ( x - 1 ) + 3 x = - x + 1
2 x - 2 + 3 x + x = 1 
6 x = 1 + 2  ⇒ x = 3/6 = 1/2 ∈ Q

 2 ( 1 - x ) + 3 ( x - 2 ) = 4 ( x - 5 ) + 3
2 - x + 3 x - 6 = 4 x - 20 + 3 
2 x - 4 x = - 17 + 4 
- 2 x = - 13    l : ( - ) 
x = 13/2 = 6 intregi si 1/2 = 6,5 ∈ Q

Answer 2

7x - 49 = 0
7x=49 + 0
7x=49
x=7

3x - 11 = 0
3x=11 + 0
3x=11
x=3,(6)

-3/4 x+5/6=0
-3/4 x=-5/6
5×4x=6×3
x=20x=18
x=18/20
x=9/10

-3x+27=0
-3x=27-0
-3x=27
-x=9
x=9

2(x-1)+3x=-x+1
2x-2+3x+x=1
6x=1+2
x=3/6
x=1/2

2(1-x)+3(x-2)=4(x-5)+3
2-x+3x-6=4x-20+3
2x-4x=-17+4
-2x=-13x
x=13/2=
x=6 1/2
x=6,5





( acolo la ultima la 6 1/2 sa stii ca e 6 intreg 1/2 )