Matematică, întrebare adresată de oanaioanacucora, 9 ani în urmă

Rezolvati in R ecuatiile: a)1/2•{1/2•[1/2•(x+1/2)-1/2]-1/2}-1/2=1/2 b)1/9•{1/7•[1/5•(3x+4)+3]+4}+3=7/2 URGENT

Răspunsuri la întrebare

Răspuns de CarMina03
2
a)1/2•{1/2•[1/2•(x+1/2)-1/2]-1/2}-1/2=1/2
1/2•{1/2•[1/2•(x+1/2)-1/2]-1/2}=1/2+1/2
1/2•{1/2•[1/2•(x+1/2)-1/2]-1/2}=1
1/2•[1/2•(x+1/2)-1/2]-1/2=1:1/2
1/2•[1/2•(x+1/2)-1/2]-1/2=2
1/2•[1/2•(x+1/2)-1/2]=2+1/2
1/2•[1/2•(x+1/2)-1/2]=5/2
1/2•(x+1/2)-1/2=5/2:1/2
1/2•(x+1/2)-1/2=5
1/2•(x+1/2)=5+1/2
1/2•(x+1/2)=11/2
x+1/2=11/2:1/2
x+1/2=11
x=11-1/2
x=21/2
b)1/9•{1/7•[1/5•(3x+4)+3]+4}+3=7/2
1/9•{1/7•[1/5•(3x+4)+3]+4}=7/2-3
1/9•{1/7•[1/5•(3x+4)+3]+4}=1/2
1/7•[1/5•(3x+4)+3]+4=1/2:1/9
1/7•[1/5•(3x+4)+3]+4=9/2
1/7•[1/5•(3x+4)+3]=9/2-4
1/7•[1/5•(3x+4)+3]=1/2
1/5•(3x+4)+3=1/2:1/7
1/5•(3x+4)+3=7/2
1/5•(3x+4)=7/2-3

1/5•(3x+4)=1/2
3x+4=1/2:1/5
3x+4=5/2

3x=5/2-4

3x=-3/2

x=-3/2:3

x=-1/2
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