Question

rezolvati in R ecuatiile: a) 1/x-2+1/x-5+3x^/4(x-2)(x-5)=0​

Answer 1

Răspuns:

Explicație pas cu pas:

1/(x-2) + 1/(x-5) + 3x/[4(x-2)(x-5)] = 0

x ≠ {2 ; 5}

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=> 4(x-2)+4(x-5)+3x= 0 <=>

4x-8+4x-9+3x = 0 <=> 11x-17 = 0

11x = 17 => x = 17/11