Question

rezolvati in R inecuatiile: 6(x-3)-10<_2(2x+1)​

Answer 1

Răspuns:

x ∈(-∞ , 15]

Explicație pas cu pas:

6(x-3)-10 ≤ 2(2x+1)​  <=>

6x-18-10 ≤ 4x +2 <=>

6x-28 ≤ 4x+2 <=>

6x-4x ≤ 28+2 <=>

2x ≤ 30 I:2

x ≤ 15

x ∈(-∞ , 15]

Answer 2

Răspuns:

Salutare!

$6(x - 3) - 10 \leqslant 2(2x + 1) =6x - 18 - 10 \leqslant 4x + 2 = 6x - 28 \leqslant 4x + 2 = 6x - 4x \leqslant 2 + 28 = 2x \leqslant 30 = x \leqslant 15$

x€(-infinit,15]