Question

Rezolvati in R
x-1 supra 2 + 2x-1 supra 6 mai mare sau egal cu 1
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Answer 1

Răspuns:

sper ca te am ajutat!! :)

Answer 2

$\it \dfrac{^{3)}x-1}{\ 2}+\dfrac{2x-1}{6}\ \geq\ ^{6)}1 \Rightarrow 3x-3+2x-1\geq6 \Rightarrow3x+2x\geq6+1+3 \Rightarrow \\ \\ \\ \Rightarrow 5x\geq 10|_{:5} \Rightarrow x\geq2 \Rightarrow x\in [2,\ \ \infty )$