Question

rezolvati in R x la patrat -3x+2=0

Answer 1

x²-3x+2=0     unde  a=1    b=-3    c=2
Δ=b²-4ac
Δ=(-3²)-4×1×2
Δ=9-8=1
X₁=-b+√Δ/2a
X₁=3+1/2=4/2=2
X₂=-b-√Δ/2a
X₂=3-1/2=2/2=1
Deci avem 2 solutii pt x  (X₁=2   si   X₂=1  ) ambele solutii fiind pozitive

Answer 2

$\displaystyle x^2-3x+2=0 \\ a=1,b=-3,c=2 \\ \Delta=b^2-4ac=3^2-4 \cdot 1 \cdot 2=9-8=1\ \textgreater \ 0 \\ x_1= \frac{3+1}{2} = \frac{4}{2} =2 \\ \\ x_2= \frac{3-1}{2} = \frac{2}{2} =1 \\ \\ S=\{1;2\}$