Question

rezolvati in scris 3²⁺⁴⁺⁶⁺...⁺²⁰=3 la n*(n+1)
ce nr e"n"
urgent!!!!!!!!!!

Answer 1

$2+4+6+......+20=$... este de forma 2+4+6+...+2n=n*(n+1)
$2n=20 \\ n=\frac{20}{2} \\ n=10 \\ S=10*(10+1)=10*11=110 \\ 3^{2+4+6+...+20}=3^{110}$