Question

Rezolvati in Z ecuatia 5×{3+4[1+2×(×supra 3-4)]}+11=46


dau 5 steluteeee.....​

Answer 1

Răspuns:

$5*(3+4[1+2*(\frac{x}{3}-4)])+11=46$

$5*[3+4(1+2*\frac{x-12}{3})]=35 /:5$

$3+4(1+\frac{2x-24}{3})=7$

$4(1+\frac{2x-24}{3})=4/:4$

$1+\frac{2x-24}{3}=1$

$\frac{2x-24}{3}=0 /*3$

2x-24=0 /:2 ⇒ x=12

Explicație pas cu pas: