Question

Rezolvati in Z ecuatiile.
2(x-3)+1=11
5(2x+1)-7(x-2)=1
3(2x-1)-2(3x-5)=7
27-3(2x+3)=2(1-3x)
4(x-2)-3x+5
Multumesc.

Answer 1

2(x-3)+1=11
2x+6+1=11
2x=11-7
2x=4
x=4:2
x=2
5(2x+1)-7(x-2)=1
10x+5-7x+14=1
3x+19=1
3x=1-19
3x=-18
x=-18:3
x=-6
3(2x-1)-2(3x-5)=7
6x-3-6x+10=7
7=7(A)=>x poate avea orice valoare din Z
27-3(2x+3)=2(1-3x)
27-6x-9=2-6x
18-2=-6x+6x
16=0(F)
x €∅
Cred ca ai vrut sa scrii:
4(x-2)-3x=5
4x-8-3x=5
x=5+8
x=13