Question

Rezolvati inecuatia 2² x(a-3²)≥ 7²-3 la puterea 0a,unde a este numar natural.

Answer 1

4·(a-9)≥49-1
4a-36≥49-1
4a≥48+36
4a≥84
a≥21
a∈N⇒a={21,22,23,∞}

Answer 2

[tex]2^2(a-3^2) \geq 7^2-3^0\\ 4(a-9) \geq 49-1\\ 4a-36 \geq 48\\ 4a \geq 48+36\\ 4a \geq 84\\ a \geq 21\\ S[21.,....infinit][/tex]