Question

rezolvati inecuatia 3x la a doua -11x +6< sau egal decat 0
pls

Answer 1

3x²-11x+6<0
Δ=-11²-4·3·6
Δ=121-72
Δ=49
x₁<$\frac{11+7}{6}$
x₁<3
x₂<$\frac{11-7}{6}$
x₂<$\frac{2}{3}$

Answer 2

$3x^2-11x+6\ \textless \ 0$

[tex]3x^2-11x+6=0 a=3 b=-11 c=6 delta=b^2-4ac = (-11)^2-4*3*6=121-72=49 [/tex]

[tex] x_{1}= \frac{11+7}{6}= \frac{18}{6} =3 x_{2}= \frac{11-7}{6}= \frac{4}{6}= \frac{2}{3} [/tex]


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