Question

Rezolvati inecuatia

$( \sqrt[3]{2}) ^x \ \textgreater \ \frac{1}{8}$

Answer 1

[tex]( \sqrt[3]{2} )^x \ \textgreater \ \frac{1}{8} [/tex]
[tex] 2^{ \frac{1}{3}x } \ \textgreater \ 2^{-3} [/tex]
[tex] folosind a^x\ \textgreater \ a^y [/tex]
[tex] \frac{1}{3}x \ \textgreater \ -3 [/tex]
$x \ \textgreater \ -9$

deci folosesti a^x > a^y si a > 1 si x>y