Question

Rezolvati inecuațiile in Z
a)3x>3
b)2x<5
c)-3x>=-6
d)-4x<=10​

Answer 1

Răspuns:

• Multimea Z = multimea numerelor intregi .

a)

3x > 3

x > 3 : 3

x > 1

x = { 2,3, 4, ......  + ∞}

b)

2x < 5

x < 5 : 2

x < 2,5

x = { - ∞, .... 1, 2}

c)

-3x ≥ -6

x ≥ - 6 : (-3)

x ≤ 2

x = {- ∞, ..... 1, 2}

d)

-4x ≤ 10

x ≤ 10 : (-4)

x ≤ - 2,5

x = { -∞, ..... -4, -3} ​

Answer 2

.....................

a) 3x>3=>x>3:3=>x>1=>x=2,3,4,......(infinit)

b)2x<5=>x<5:2=>x<2,5=>x=2,1,0,-1,-2,-3.............

c)-3x>sau egal-6=>x>sau egal-6:(-3)=>x≤2=>x=1,0,-1,-2

d) -4x<10=>x<10:(-4)=>x<-2,5 =>X=-3,-4,-5,-6......