Question

rezolvati? log2(xla a 2a -4x+4)=0

Answer 1

Conditii de existenta pentru logaritm:

$x^2-4x+4\ \textgreater \ 0 \\ (x-2)^2\ \textgreater \ 0 \\ x \neq 2$

Rezolvam ecuatia:

$log_2(x^2-4x+4)=0 \\ x^2-4x+4=2^0 \\ x^2-4x+4=1 \\ x^2-4x+3=0 \\ \Delta=16-12=4 \\ x_1= \frac{4+2}{2}=3 \\ x_2= \frac{4-2}{2}=1$