Question

Rezolvati pe 10 tot va rog dau coroana

Answer 1

Eu inca nu am ajuns la fractii

Answer 2

$a) \frac{x}{2} = \frac{8}{x} = > {x}^{2} = 16 = > x = \sqrt{16} = 4$
**peste tot inmultesti pe diagonala
$b) \frac{6}{x} = \frac{x}{4} = > {x}^{2} = 24 = > x = \sqrt{24} = 2 \sqrt{6}$
$c) \frac{2x}{7} = \frac{8}{7x }$
$14 {x}^{2} = 56 \\ {x}^{2} = \frac{56}{14} = > {x}^{2} = 4$
x=2
$d) \frac{3}{4x } = \frac{3x}{4}$
$12x ^{2} = 12$
${x}^{2} = 1$
$x = 1$
$e) \frac{9x}{5} = \frac{5}{x}$
$9 {x}^{2} = 25$
$x ^{2} = \frac{25}{9}$
$x = \frac{5}{3}$
$f) \frac{7 x}{6} = \frac{4}{3x}$
$21 {x}^{2} = 24$
${x}^{2} = \frac{24}{21}$
${x}^{2} = \frac{8}{7}$
$x = \frac{2 \sqrt{2} }{ \sqrt{7} }$
**rationalizezi
$x = \frac{2 \sqrt{14} }{7}$