Question

Rezolvati prin metoda reducerii:
3x¸¸+2y-1 supra6 + x-y-5 supra2 =-6
x-3y+1supra4 - 2x-y-1supra3=1

Answer 1

Răspuns:

x = -49/60; y = -1/15

Explicație pas cu pas:

3x+2y-1/6 + x-y-³⁾5/2 = -6

x -3y+³⁾1/4 -2x-y-⁴⁾1/3 = 1 <=>

4x+y - 16/6 = -6 <=>

³⁾4x+³⁾y - 8/3 = ³⁾-6

¹²⁾-x-¹²⁾4y -1/12 = ¹²⁾1 =>

12x+3y-8 = -18

-12x-48y-1= 12 <=>

12x+3y = -18+8 = -10

-12x-48y = 13

___________

-45y = 13-10 = 3 => y =3/(-45) => y =  -1/15

12x +3·(-1/15) = -10 <=> 12x- 1/5 = -10 => ⁵⁾12x = -⁵⁾10+1/5 =>

60x = -49 => x = -49/60

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