Question

rezolvati prin metoda reducerii sistemele:
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Answer 1

Răspuns:

a)x+y=3

x-y=7

x=3

x=7

2x=10

x=5

5+y=3

y=3-5

y=-2

c)x+y=7|*-1

-4x+y=-3

-x-y=7

-4x+y=-3

x=7

-4x=-3

-3x=4

x=4/-3

4/3+y=7

1.(3)+y=7

y=7-1.(3)

y=5.67

-

e)3x+2y=10|*8

7x-8y=-2|*2

24x+16y=80

14x-16y=-4

24x=80

14x=-4

38x=76

x=76/38

x=2

6+2y=10

2y=4

y=2

x=y=2