Question

rezolvati prin metoda substitutiei sistemele​

Answer 1

Răspuns:

b)2x+3y=5|-2x

x+3y=6

3y=5-2x

x+5-2x=6

3y=5-2x

-3x+5=6

-3x=1

x=1/3

3y=5-0.6

3y=4.4

y=4.4/3

d)

3x+y=-6

2x-2y=5

y=-6-3x

2x-2*-6-3x=5

y=-6-3x

2x-12-3x=5

y=-6-3x

5x-12=5

5x=17

x=17/5 aprox 3

y=-6+3*3.5

y=-6+10.5

y=-16.5

f)2x+5y=-11|*-4

3x+4y=10|*5

-8x-20y=44

15x+20y=50

8x=44

15x=50

23x=94

x=94/23

x=4

12+4y=10

4y=-2

y=-0.5