Question

Rezolvați radicalii coronița

Answer 1

radical de ordin 5 din 32 = 2 pt ca 2^5 = 32

8^(-1/5) = (2^3)^(-1/5) = 2^(-3/5)

1/4 = 4^(-1) = (2^2)^(-1) = 2^(-2)

[(2^(-2)]^(-2/5) = 2^(4/5)

$\frac{2^{\frac{8}{5} }*2 *2^{\frac{-3}{5} }  }{2^{\frac{4}{5} } } = \frac{2^{\frac{8}{5} +1-\frac{3}{5} } }{2^{\frac{4}{5} } } = 2^{2} :2^{\frac{4}{5} } = 2^{2-\frac{4}{5} } = 2^{\frac{6}{5} }$