Question

rezolvati sistemul de ecuati prin metoda substitutei
x=2
3x+2y=9
si prin metoda reducerii
x+y=10
x-y=2

Answer 1

Prin metoda substitutiei:
x=2
3x2+2y=9 <=>6+2y=9 <=> 2y=9-6 <=>2y=3 <=>y=3/2
S={(2;3/2)}
Prin metoda reducerii:
x+y=10 <=>2x=12 <=> x=6
x-y=2   <=>x+y=10<=> 6+y=10 <=> y=10=6 <=>y=4
S={(6;4)}