Question

Rezolvați sistemul de ecuații:
{2(x+2y)-3(x+3y)=-8
3(2x + y)2(3x-2y)=7

Answer 1

$2(x + 2y) - 3(x + 3y) = - 8 \\ 3(2x + y)2(3x - 2y) = 7 \\ \\ - x - 5y = 8 \\ 12x - y = 7 \\ - 12x - 60y = 96 \\ 12x - y = 7 \\ - 61y = 103 \\ y = - \frac{103}{61} \\ \\ - x - 5 \times ( - \frac{103}{61} ) = 8 \\ - x + \frac{515}{61} = 8 \\ - x = - \frac{27}{61} \\ x = \frac{27}{61} \\ \\ \\ y = \frac{103}{61} \\ x = \frac{27}{61}$

sper ca te-am ajutat!