Question

Rezolvati sistemul de inecuatie. 4x+1≤-2x+7. 3x-20<8x-10

Answer 1

Răspuns:

$4x + 1 \leqslant - 2x + 7 \\ 3x - 20 < 8x - 10$

$4x + 2x \leqslant 7 - 1 \\ 3x - 8 x< - 10 + 20$

$6x \leqslant 6 \\ - 5x < 10$

$x \leqslant 1 \\ x > - 2$

S(-2 , 1]

Succes