Question

Rezolvati sistemul: x*y=32
                            2(x+y)=36

Answer 1

$x*y=32=>x= \frac{32}{y}$
$2( \frac{32}{y} +y)=36<=> \frac{32}{y} +y=18<=>32+y^2=18y$
$<=>y^2-18y+32=0<=>y^2-16y-2y+32=0$
$<=>y(y-16)-2(y-16)=0<=>(y-16)(y-2)=0$
$y-16=0=>y=16$ sau $y-2=0=>y=2$
$x= \frac{32}{y} = \frac{32}{2} =16$