Question

Rezolvati urmatoarea ecuatie:
$log_{rad6}$ x= 2$2log_{rad6}$ 4- $log_{rad6}$ 2+$log_{rad6}$ 5

Answer 1

$log _{\sqrt{6} }x=2log_{\sqrt{6}}4-log_{\sqrt6}}2+log_{\sqrt6}}5$
x>0 x∈(0,∞)
[tex]log_{\sqrt6}x=log_{\sqrt6}4^2-log_{\sqrt6}2+log_{\sqrt6}5 =\ \textgreater \ log_{\sqrt6}x=log_{\sqrt6}({ \frac{16}{2} *5)=\ \textgreater \ [/tex]
$log_{\sqrt6}x=log_{\sqrt6}40=\ \textgreater \ x=40$