Question

Rezolvati urmatoarea integrala.$\int { \frac{1}{ \sqrt{x+1} } } \, dx$

Answer 1

Stim ca : $( \sqrt{x+1})'= \frac{1}{2 \sqrt{x+1} }$, deci $\int\limits { \frac{1}{ \sqrt{x+1} } } \, dx =2\int\limits { \frac{1}{ 2\sqrt{x+1} } } \, dx = \int\limits {( \sqrt{x+1})' } \, dx = \sqrt{x+1} +C$