Question

Rezolvati va rog din poza!!!
Multumesc!

Answer 1

Răspuns:

h)$\sqrt{9^{2}-6^{2}+2^{2} }$=$\sqrt{81-36+4}$=$\sqrt{49}$=7

i)$\sqrt{100}$·$\sqrt{16}$-$\sqrt{144}$=10·4-12=40-12=28

j) 2,(3)·$\sqrt{0,(1)}$+$\sqrt{\frac{324}{25} }$:$\sqrt{\frac{81}{225} }$-$\sqrt{1024}$:$\sqrt{64}$=

$\frac{21}{9}$·$\sqrt{\frac{1}{9} }$+$\frac{18}{5}$:$\frac{9}{15}$-$8\sqrt{2}$:8=

$\frac{21}{9}$·$\frac{1}{3}$+$\frac{18}{5}$:$\frac{15}{9}$-$\sqrt{2}$=

$\frac{21}{27}$+6-$\sqrt{2}$=$\frac{7}{9}$+6-$\sqrt{2}$