Question

rezolvati va rog mult pe lung daca puteti
a)√3(√3-√2)+√6
b)√3(√2+3+√3)-(√3+√8)×2√2
c)(2√6+√54)÷√6-(8√5-√45)÷√5
d)2√2×(√8-√50)+4√12÷√3
e)3/√2 -√9/√32+ √49/√8-√25/√2

Answer 1

a)√3(√3-√2)+√6) = √3*√3-√3*√2+√6 =3-√6+√6 = 3

b)√3(√2+3+√3)-(√3+√8)×2√2=√3*√2+√3*3+√3*√3 - 2√2*√3-2√2*√8 = √6+3√3+3+ -2√6-2√16 = -√6+3√3+3-8=-√6+3√3-5

c)(2√6+√54)÷√6-(8√5-√45)÷√5=2√6+√6*9) )÷√6-(8√5-√5*9)÷√5=2√6+3√6÷√6-8√5+3√5÷√5=5√6÷√6-5√5÷√5=4√6-4√5=4(√6-√5)

dacă e ok așa, atunci trimit și restul.

Answer 2

a) √3(√3–√2)+√6 =√3•√3- √3•√2+√6 =√9-√6+√6 =√9-0 =√9 =3 b) √3(√2+3+√3)-2√2(√3+√8) =√6+3√3+√9-2√6+2√16 =√6+3√3+√9–2√6+2√16 =√6+3√3+3–2√6+2√16 =-√6+3√3+3-2√6+2√16 c) (2√6+√54): √6-(8√5-√45): √5 =(2√6+3√6): √6-(8√5-3√5):√5 =5√6:√6-5√5:√5 =5-5 =0 d) 2√2(√8-√50)+4√12:√3 =2√2(2√2-5√2)+4√4 =2√2•(-3√2)+4√4 =-6√4+4√4 =-2√4 e)3/√2-√9/√32+√49/√8-√25/√2 =3/√2–3/√32+7/√8–5/√2 =3/√2–3/4√2+7/2√2–5/√2(le raționalizăm cu √2) =3√2/1–3√2/4+7√2/2–5√2/1(aducem la numitor comun) =12√2–3√2+14√2–20√2 =9√2+14√2–20√2 =23√2–20√2 =3√2