Question

Rezolvati varog:
A)5(3x-1)+4=2(3x+20)
B)7(3x+2)=8(x+3)
C)5(2x+4)-4=46
D)8(x+3)+41=105

Answer 1

$\displaystyle a). 5(3x-1)+4=2(3x+20) \\ 15x-5+4=6x+40 \\ 15x-6x=40+5-4 \\ 9x=41 \\ x= \frac{41}{9} \\ \\ b).7(3x+2)=8(x+3) \\ 21x+14=8x+24 \\ 21x-8x=24-14 \\ 13x=10 \\ x= \frac{10}{13}$

$\displaystyle c).5(2x+4)-4=46 \\ 10x+20-4=46 \\ 10x=46-20+4 \\ 10x=30 \\ x= \frac{30}{10} \\ x=3 \\ \\ d).8(x+3)+41=105 \\ 8x+24+41=105 \\ 8x=105-24-41 \\ 8x=40 \\ x= \frac{40}{8} \\ x=5$