Question

rezolvatimi va rog mult mult de la 1 pina la 12...e urgent,va implor,dau 100 punkte

Answer 1

$1)( \frac{3}{4}+ \frac{1}{4}) ^{2015}= 1^{2015}=1 \\ 2)dist=2 \sqrt{2};a=4 \sqrt{2} \\ d=a \sqrt{2}=4 \sqrt{2}* \sqrt{2}=8 cm$
3)240----------100%
   x--------------120%
                                     x=(240*120)/100=288 lei
4)4x+7<x-2 ⇔3x<-9 ⇔x<-3 ;x∈(-∞;-3).Cea mai mare solutie intreaga este -2
5)L=2πR⇒12π=2πR⇒R=6
   A=πR²=36π
$6)F(x)= \frac{x(x^2-9)}{ x^{2} (x+3)} = \frac{x(x-3)(x+3)}{ x^{2} (x+3)} = \frac{x-3}{x}$
7)a+b=25 si 2a+3b=65
   2a+2b=50 si 2a+3b=65 le scadem si obtinem
b=15
a=10
8)a=1-2√+3=4-2√3 ;b=√49·3-2√25·3+3√4·3+4-√3=7√3-10√3+6√3+4-√3=
  =4+2√3
a)  a·b=(4-2√3)(4+2√3)=16-12=4
b)media aritmetica m=(4+2√3+4-2√3+7)/3=15*5=5
9)Alat=2πRG=10·20π=200π
  V=πR²H=25·20π=500π
10)x-1-2y=10  si 4x+1-y=24
     x-2y=11  si 4x-y=23
inmultim prima ecuatie cu 4

4x-8y=44               x=11+2y             x=11+2(-3)      x=5
4x-y=23                 -7y=21                y=-3                y=-3

11)P(1)=1-3-m+12=10-m; 10-m=6⇔m=4
     P(x)=x³-3x²-4x+12=x²(x-3)-4(x-3)=(x-3)(x²-4)=(x-3)(x-2)(x+2)
12)A=(ab)/2 ⇔96=(ab)/2⇔192=ab si a/b=4

   a=4b         a=4b               a=16√3
  4b²=192     b²=48              b=4√3

c²=a²+b² ;c²=(16√3)²+(4√3)²=768+48=816
c=√816=√16*51=4√51
P=16√3+4√3+4√51=20√3+4√51=4√3(5+√17)