Question

rezolvazi in multimea nr intregi ecuatile 2(2x+5)-9=13
42-5(2x-9)=29
3[2(2x-3)-9]-8=7
3(4x-5)+32=27+2(3x-2)

Va rog mult repedee​

Answer 1

Răspuns:

2(2x+5)-9=13

4x+10-9=13

4x+10=22

4x=12

x=3

42-5(2x-9)=29

42-10x+45=29

42-10x=-16

-10x=-58

x=5,8

3[2(2x-3)-9]-8=7

3(4x-6-9)=15

12x-18-27=15

12x-18=42

12x=60

x=5

3(4x-5)+32=27+2(3x-2)

12x-15+32=27+6x-4

12x-6x=27-4-32+15

6x=23-17

6x=6

x=1