Question

Rezultatul calculului : (2x-3)² + (3x+2)² = ?

Answer 1

(2x-3)²+(3x+2)²=
(2x)²-2*2x*3+3²+(3x)²+2*3x*2+2²=
4x²-12x+9+9x²+12x+4=
(-12x cu +12x s reduc si ne da 0)

4x²+9+9x²+4=
13x²+13

Sper ca te-am ajutat

Answer 2

$(2x-3)^2+(3x+2)^2=(2x)^2-2 \cdot 2x \cdot 3+3^2+(3x)^2+2 \cdot 3x \cdot 2+2^2= \\ =4x^2-12x+9+9x^2+12x+4=13x^2+13$