Question

rezultatul calculului:(aa4+5a+1):(a5a+a5)

Answer 1

 $Δ=4a^{2}+5a+1 =\ \textgreater \ = 25 - 16 = 9 \\ a_{1} = \frac{-5-3}{8} =-1 \\\\ a_{2}= \frac{-5+3}{8} = - \frac{1}{4} \\ \\ 5a^2+5a+0\ \\ a=5\\ b=5\\ c=0\\ de \ aici \ continui \ tu$