Question

rezultatul ecuatiei (m-3) x²-2(3m-4)x+7m-6=0

Answer 1

(m-3)x²-2(3m-4)x+7m-6=0

Δ=(-2(3m-4)²-4(m-3)(7m-6)

Δ=4(3m-4)²-4(7m²-27m+18)

Δ=4(9m²-24m+16)-28m²+108m-72
Δ=36m²-96m+64-28m²+108-72
Δ=8m²+12m-8≥0

Δ₁=144+256=400
m₁=(-12+20)/16=1/2
m₂=(-12-20)/16=-2

m                    I -∞                    -2            1/2                    +∞
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8m²+12m-8  I++++++++++++0-------------)+++++++++++++++