Question

Rezultatul la acest exercitiu
(2√3+1)²

Answer 1

$\boxed{(a+b)^2=a^2+2ab+b^2} \\\\ \text{Aplicam formula de sus , formula binomului}\\ (2 \sqrt{3} +1)^2=(2 \sqrt{3})^2 +2*2 \sqrt{3} *1+1^2\\(2 \sqrt{3} +1)^2=12+ 4\sqrt{3}+1\\(2 \sqrt{3} +1)^2=\underline{13+ 4\sqrt{3} }$