Question

Rezvolarea acestor probleme, urgent, va rog!
1. (1+i)^2 - 2i = 0, unde i^2 = -1;
2. Stiind ca i^2 = -1, sa se calculeze (3+2i) - (2+3i)^2;
3. Sa se rezolve in R ecuatia 5^x + 5^1-x = 6;
4. Determinati multimea valorilor functiei f:R -> R, f(x) = 5x^2 - 4x + 4.

Answer 1

Răspuns:

Explicație pas cu pas:

(1+i)²-2i=1+2i-1+2i=0 adevarat

2.

3+2i-(4+12i-9)=3+2i+5-12i=8-10i

3.5^x=y

y+5/y=6

y²-6y+5=0

y1=1...5^x=1...x=0

y2=5...5^x=5....x=1

4, D=[-Δ/4a;∞)

Δ=16-80=-64

-Δ/4a=64/20=16/5

D=[16/5;∞)