Question

!!!!! rpddd !!!! va rog​

Answer 1

Răspuns:

Ioana

Explicație pas cu pas:

x = √(7-4√3) = √(2-√3)²  = I 2-√3 I = 2-√3

(2-√3)² = 2²-2·2·√3+(√3)² = 4-4√3+3 = 7-4√3

y = 2+√3

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ma (x;y) = (x+y)/2 = (2+√3+2-√3)/2 = 4/2 = 2

mg (x;y) = √(x·y) = √[(2+√3)(2-√3)] = √(4-3) = 1

ma (x;y) - mg (x;y) = 2-1 = 1

Ioana a calculat corect.