Question

rpede cum se calculaeaza inaltimea intr-un trapez isoscel stiind ca baza mica are 6 cm si cea mare are 12 cm????/va rogggg

Answer 1

Cobor perpendicularele AE si BF (E,F∈CD).
EF=AB=6cm.

$DE=CF= \frac{CD-EF}{2} = \frac{12-6}{2}= \frac{6}{2}=3(cm).$

DF=DE+EF=3+6=9 (cm).

Aplic teorema inaltimii in ΔBDC-dreptunghic in B:

$BF= \sqrt{DF*CF}= \sqrt{9*3}= 3\sqrt{3}(cm).$

Inaltimea are lungimea de $3 \sqrt{3}$cm.