Question

rzolvati in multimea nr naturale 600+12*(x+2)=1305-3*(9 la puterea 2+3*18)

Answer 1

[tex]600+12*(x+2)=1305-3*(9^2+3*18)\\ 600+12x+24=1305-3*(81+54)\\ 624+12x=1305-243-162\\ 624+12x=900\\12x=900-624\\ 12x=276\\ x=276:12\\ x=23[/tex]
S={23}