Question

Rzolvati in R inecuatia :
(x+2)la puterea a 2-a - (x+2)(x-5)<14x-7

Answer 1

(x² +4x + 4) - (x² -5x +2x -10 ) -14x +7<0
x² +4x +4 -x² +5x -2x +10 -14x +7 <0
-7x +21 <0
-7x < -21
x>21/7
x> 3
x∈ (3,+∞)

Answer 2

$(x+2)^{2} -(x+2)(x-5) < 14x-7$
$x^{2} +4x+4 - ( x^{2} -5x+2x-10)<14x-7$
$x^{2} +4x+4 - x^{2} +3x+10)<14x-7$
$7x+14<14x-7$
$7x+14-14x+7<0$
$-7x+21<0$
$-7x<-21$
$x>3$ , deoarece am mutat numar cu - si se schimba semnul . :*