Question

sā se afle a+b unde a=2radicaldin3×(-5radical din3)+29 şi b=6radical din18÷(2radicaldin2)-8​

Answer 1

Salut! ♡

a=

$2 \sqrt{3} \times ( - 5 \sqrt{3} ) + 29$

$- 2 \sqrt{3} \times 5 \sqrt{3} + 29$

$- 2 \times 3 \times 5 + 29$

$- 30 + 29$

$- 1$

b=

$6 \sqrt{18} \div (2 \sqrt{2} ) - 8$

$3 \sqrt{9} - 8$

$3 \times 3 - 8$

$9 - 8 \\ 1$

a+b= (-1)+1= 0

Succes!

Answer 2

Răspuns:

Explicație pas cu pas: