Question

sa calculeze cineva pls sunt 3 subpuncte

Answer 1

$\it a)\ \ \dfrac{8!+7!}{6!}= \dfrac{\not7!(8+1)}{\dfrac{\not7!}{7}}=\dfrac{9}{\dfrac{1}{7}}=9\cdot7=63\\ \\ \\ b)\ \Big{C}_{10}^3=\dfrac{10!}{3!(10-3)!}=\dfrac{7!\cdot8\cdot9\cdot10}{1\cdot2\cdot3\cdot7!}=\dfrac{720}{6}=120\\ \\ \\ c)\ \ \dfrac{\Big A_{10}^3}{P_3}=\Big C_{10}^3=120$

Answer 2

Răspuns: Ai rezolvarea mai jos pentru fiecare punct in parte

Explicație pas cu pas:

$\bf a)~~\dfrac{8!+7!}{6!}=\dfrac{6!\cdot7\cdot8+6!\cdot7}{6!}=\dfrac{ \not6!\cdot(56+7)}{\not6!}=\dfrac{ 1\cdot 63}{1}= 63$

$\it~~$

$\bf b)~ C^{3}_{10}=\dfrac{10!}{~3!\cdot(10-3)!~}=\dfrac{~7!\cdot8\cdot9\cdot10~}{~1\cdot2\cdot3\cdot7!~}=\dfrac{\not7!\cdot8\cdot9\cdot10~}{~1\cdot2\cdot3\cdot\not7!~}=\dfrac{720}{6}=120$

$\it~~$

$\bf c)~~ \dfrac{~A^{3}_{10}~}{P_{3}}=C^{3}_{10} = 120$

#copaceibrainly

P.S.: Daca esti pe telefon te rog sa glisezi spre stânga pentru a vedea întreaga rezolvare