Question

Sa ma ajute cineva va rog

Answer 1

$\log_{n}27 \in \mathbb{N} \\ \\ 3^3 = 27 \Rightarrow 3 = \log_{3}27\\ \\ 27^1 = 27 \Rightarrow 1 = \log_{27}27\\ \\ \Rightarrow n \in \{3;\, 27\}$

Answer 2

$log_{n}27 \: \: aparține \: N$

$27 = {3}^{3} \: \: \: \: deci \: \: = > \: = log_{3}27$

$27 = 27 {}^{1} \: \: \: deci \: \: = > = log_{27}27$

$deci \: N apartine\: \: (3,27)$