Question

Sa se afle 3 nr naturale pare consecutive care au suma 234

Answer 1

n+n+2+n+4=234
3n=234-6
3n=228
n=228/3
n=76
primul nr
78 al doilea 
80 al treilea

Answer 2

a+a+2+a+4=234;3a+6=234;3a=234-6=228;a=228:3=76;a+2=76+2=78;a+4=76+4= 80; numerele pare consecutive sunt:76;78;80