Question

să se afle 4 nr. naturale consecutive care au suma 1230

Answer 1

a + b + c + d = 1,230
a , b , c , d - nr. consecutive
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a = ?
b = ?
c = ?
d = ?

PRIN METODA FIGURATIVA :

a |---|
b |---|--|
c |---|--|--|
d |---|--|--|--|

4 p + 6 = 1,230
4 p = 1,230 - 6
4 p = 1,224
p = 1,224 : 4
p = 306

a = 306
b = 306 + 1
b = 307
c = 306 + 1 + 1
c = 307 + 1
c = 308
d = 306 + 1 + 1 + 1
d = 307 + 1 + 1
d = 308 + 1
d = 309 .

Answer 2

Fie x, x+1,x+2 si x+3 numerele cautate, atunci:
x+x+1+x+2+x+3=1230 => 4x+6=1230 =>4x=1230-6=>4x=1224=>x=1224÷4=> x=306
x+1=307
x+2=308
x+3=309