Question

Sa se afle
a)numarul de molecule continute intr.o masa m=1g de apa
b)raza unei molecule (molecula fiind considerata sferica)

Answer 1

N=ν*Na

ν=m/M

N=Na*m/M

N=6,02*10²³*1/18=3,3(4)*10²²

V=4πR³/3
R=∛(3*V/4π)

V=m'/ρ

m'=m/N⇒V=m/(N*ρ)⇒R=∛[3*m/(N*ρ*4π)]
R≈1,92*10⁻⁸cm