Question

sa se afle c,m,m,d,c si c,m,m,n al numerelor 72si80 120 si 144 198si180 288si360 432si600 976si72 1890si2268 3780si4936 324si 5769

Answer 1

288=$2^{5} * 3^{2}$
360=$2^{3} * 3^{2} * 5$
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(288;360)=$2^{3} * 3^{2} =8*9=72$
[288;360]=$2^{5} * 3^{2} *5=32*9*5=160*9=1440$

432=$2^{4} * 3^{2}$
600=$2^{3} *3* 5^{2}$
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(432;600)=$2^{3} * 3=8*3=24$
[432;600]=$2^{4} * 3^{2} * 5^{2}=16*9*25=400*9=3600$

976=$2^{4} *61$
72=$2^{3} * 3^{2}$
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(976;72)=$2^{3} =8$
[976;72]=$2^{4} * 3^{2} *61=16*9*61=976*9=8784$

1890=$2* 3^{2} *5*7$
2268=$2^{2} * 3^{4} *7$
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(1890;2268)=$2* 3^{3} *7=2*27*7=54*7=378$
[1890;2268]=$2^{2} * 3^{4} *5*7=4*81*5*7=4*405*7=1620*7=11340$