Question

sa se afle cel mai mic numar natural care impartit la 36 da restul 30 iar impartit la 48 da restul 42

Answer 1

n=36a+30
n=48b+42



n+6=36a+30+6=36a+36=36c
n+6=48b+42+48b+48=48d

deci 36|n+6
si
48|n+6
 atunoc cmmmc(36;48)|n+6
cmmmc(36; 48) = cmmmc(12*3; 12*4) = 12*12=144
144|n+6
 (n+6) minim=144
nminim=144-6=138

verificare 138:36=3 rest 30
138:48=2 rest 42
adevarat , bine rezolvat