Question

Sa se afle cel mai mic numar natural care impartit la 5 , da restul 1 , impartit la 8 da restul 3 si impartit la 9 da restul 4 .

Answer 1

$x:5=c_1 \ rest \ 1 \\\\ x=M_5+1 \\\\ x=M_5+5-4+1-1 \\\\ x=M_5-5+1\\\\\\ x:8=c_2 \ rest \ 3 \\\\ x=M_8+3 \\\\ x=M_8+8-5 \\\\ x=M_8-5 \\\\\\ x:9=c_3 \ rest 4 \\\\ x=M_9+4 \\\\ x=M_9+9-5 \\\\ x=M_9-5 \\\\ x=([M_5;M_8;M_9]-5)+1 \\\\ x\to cel \ mai \ mic \ nr \\\\ x=360-5+1 \\\\ \boxed{x=356}$