Question

sa se afle formula moleculara a substantei ce contine 92.31%C si 7.69 %H stiind ca 1 dm^3 din aceasta substanta cantareste la 0^0 C 1.161 g.

Answer 1

C 92,31/12=7,69/7,69=1
H 7,69/1=7,69/7,69=1
FB (CH)n
calculam n
stiind ca avem V=1dm3, 0grade celsius ⇒p=1atm T=273grad kelvin
PV=niuRT
niu=m/M
PV=m/MRT
M=mRT/PV
M=26
in FB⇒12n+n=26
n=2⇒FM C2H2 acetilena