Question

Sa se afle formula molelulara a substantei organice cu formula procentuala: 40% C, 6,66% H si 53,33% O si care are 2 atomic de oxigen in moleculă.

Answer 1

Stim:

Masa atomica a C = 12

Masa atomica a H = 1

Masa atomica a O = 16

Totodata, stim ca molecula are 2 atomi de O in ea.

2 x O = 16 x 2 = 32 g

Deci 53.33%.... 32g

6.66%....x

--------------------------------

x = 4 => H = 4 atomi

53.33%.....32g

40%.......x

-----------------------------------

x= 24 g => 24/12 => C = 2 atomi

Formula finala: C2H4O2